曝光臺 注意防騙 網曝天貓店富美金盛家居專營店坑蒙拐騙欺詐消費者

                                                               q - -02 cos a sin X
                                                                       r        2 sin a
     We bave
                                02 = 3;0
                                         = 120deg/s
                                       - 2.0942 rad/s
     Substituting, we get
                                                     p = 91.3285 deg/s
                                                 q = 10.4578 deg/s
                                                     r -. 77.1298 deg/s
We have CR - 1.2. The lift and drag coefficients are given by
                                             CL - CR cosa
                                                            CD  - CR siri ct
Substituting, we get CL - 0.9193 and CD - 0.7713.
     We have W  -. 10,915 N, p = 1.225 kg/m3, and S = 13.53 m2. The velocity of
descent is given by
UO =
     Substituting, we get Uo = 41.3236 m/s. The spin radius is given by
      R=(2 )pUo2SC
where m =  Wlg. Substitution gives R - 2.6664 m or,in terms ofwing semispan,
                                                          .
                                2R    2 x 2.6664
              b - 99822
                                      - 0.5342
Thus. we see that the spin radius is close to one-half of wing semispan.
     The inertia moments are given by
                                        Mi = rp(lz - Ix)
　
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