曝光臺 注意防騙
網曝天貓店富美金盛家居專營店坑蒙拐騙欺詐消費者
q - -02 cos a sin X
r 2 sin a
We bave
02 = 3;0
= 120deg/s
- 2.0942 rad/s
Substituting, we get
p = 91.3285 deg/s
q = 10.4578 deg/s
r -. 77.1298 deg/s
We have CR - 1.2. The lift and drag coefficients are given by
CL - CR cosa
CD - CR siri ct
Substituting, we get CL - 0.9193 and CD - 0.7713.
We have W -. 10,915 N, p = 1.225 kg/m3, and S = 13.53 m2. The velocity of
descent is given by
UO =
Substituting, we get Uo = 41.3236 m/s. The spin radius is given by
R=(2 )pUo2SC
where m = Wlg. Substitution gives R - 2.6664 m or,in terms ofwing semispan,
.
2R 2 x 2.6664
b - 99822
- 0.5342
Thus. we see that the spin radius is close to one-half of wing semispan.
The inertia moments are given by
Mi = rp(lz - Ix)
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PERFORMANCE, STABILITY, DYNAMICS, AND CONTROL4(48)