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               T-D-WsinY= g dt
                                   VI
                          ~- W,osy = ~Vdd~
                                                 g
The kinematic equations are
                                                      x -. V cos y
                                       h : V siny
Equation (2.127) can be expressed as
(2.127)
(2.128)
(2.129)
(2.130)
T-D       ldV
  W   -siny == --                   (2.131)
              g dt
Multiply both sides of Eq. (2.131) by  V  to obtain
                                         V ( TW D) _  V sin y = 21g (dc~.)                        (2.132)
Define
                                           he = h + ~rg                               (2.133)
where he is called the energy height. Using Eqs. (2.130) and (2.132), we obtain
                                            d;- = V (TW D)                               (2.134)
                                                                                (
or
                                     ll;t = Ps                           (2.135)
                  dt
Thus, the specific excess-power is more realistically equal to energy rate of climb
rather than the kinematic rate of climb dh/dt as assumed for steady-state climb.
The time to climb from a given initial energy height he, to a given final energy
height hef is given by
    hef dhe
t -                                   (2.136)
   -ei PS
T
I
Z
AIRCRAFT PERFORMANCE
E
E
s=o
hs
h r*
h3
h2
hi
                       v
　
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