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resulting from application of formulas 3-9 and 3-10A/B as appropriate.
Apply formula 3-9 to assure rollout occurs at least 500 ft above LTP elevation.
Formula 3-9 (500’ above LTP)
500 ( )
where = glidepath angle
500
tan
D TCH
θ
θ
−
=
Example
500 ( )
where = 3°
TCH = 52 feet
500 52 854835
3
. '
tan
D
θ
−
= =
Apply formula 3-10A where the initial MAS RNP value is standard (RNP 1.0) or
the MAS is based on conventional NAVAIDs.
Formula 3-10A (5 sec stabilization)
5sec ( ) ( )
TAS
where = glidepath angle
V = f
15 8
inal segment true airspeed
.44
tan TAS
D HAT TCH V
θ
θ
−
= + + ×
Example
[ ( )]
( ) ( )
TAS
5sec
Cat D 165 Kts, Altitude 2000, =3°, TCH=52, HAT=300
V = 165 1 2000 000002 = 171.60
300 52 17160 15 8 44 630703
3
.
. . .
tan
D
θ
× + ×
−
= + + × =
6/3/05 8260.52
Par 3.3 Page 3-7
Apply formula 3-10B where the initial MAS RNP value is restricted to less than
1.0.
Formula 3-10B (15 sec stabilization)
15sec ( ) ( )
TAS
where = glidepath angle
V =
15
final segment
2532
true airspeed
.
tan TAS
D HAT TCH V
θ
θ
−
= + + ×
Example
[ ( )]
( ) ( )
TAS
15sec
Cat D 165 Kts, Altitude 2000, =3°, TCH=52, HAT=300
V = 165 1 2000 000002 = 171.60
300 52 17160 15 2532 945683
3
.
. . .
tan
D
θ
× + ×
−
= + + × =
Figure 3-1. FROP
Formula 3-9
DA
Closest
FROP
500’
FROP based
on DA
LTP to DA Dist
Formula 3-10a or b
as appropriate
5 or15 seconds
3.4 DETERMINING PFAF LOCATION. (In all cases, the PFAF will be identified as a
named fix.)
The OPTIMUM alignment is a TF segment straight in from PFAF to LTP on
runway centerline extended. If necessary, the TF course may be offset by up to
3°. Where the course is offset, it must cross runway centerline extended at least
1500 out from LTP. A final segment may be designed using an RF leg segment
8260.52 6/3/05
Page 3-8 Par 3.4
when obstacles or operational requirements prevent a straight-in approach from
PFAF to LTP. Determine the along-track distance from the LTP (FTP if offset) to
the point the glidepath intercepts the intermediate segment minimum altitude
(DPFAF). Calculate DPFAF using formula 3-11. Determine which leg (TF or RF) the
PFAF is located on by comparing DPFAF to the leg lengths
Formula 3-11
( )
( )
1
Where: a = minimum intermediate altitude
b = LTP eleva
90 20 890 537
364 609 90
20 890 537
tion in feet
= glidepath angle
tch = threshold cr
sin , ,
, sin
DPFAF , ,
a b tch
θ
θ
θ
−   + 
=  − −  − − + 
ossing height
Example
( )
( )
1
a = 2000 b = 400 tch = 52 = 3°
90 3 20 890 537
364 609 90 3 29147 454
2000 400 52 20 890 537
sin , ,
, sin .
DPFAF , ,
θ
−   + 
= − −  − − + =
.
3.4.1 PFAF LOCATED ON TF LEG.
Geodetically calculate the latitude and longitude of the PFAF using the reverse
true course of the TF leg (true course – 180°) and DPFAF measured along-track
from the LTP (FTP if offset). Where the FAS consists of a single TF leg, a
Microsoft Excel spreadsheet (see figure 3-2) is provided on the AFS-420 website
to calculate DPFAF and the WGS-84 latitude and longitude of the PFAF. Go to the
following Internet link:
http://av-info.faa.gov/terps/ - Then select link: RNP SAAAR VEB.
6/3/05 8260.52
Par 3.4.1 Page 3-9
Figure 3-2. RNP PFAF and VEB Spreadsheet Example
3.4.2 PFAF Located on RF Leg.
The PFAF must be located at the initial fix of a TF or RF segment. Where the
PFAF must be located within an RF segment, the segment must be broken into
two segments, each having the same radius and turn center, with the PFAF
coincident with the initial fix of the second segment. The length in feet of the RF
　
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